Droid Engineer Archive
Thread: Detonation Power
RasalTheWise
Sat Apr 16, 2005 10:46 am
#28
RasalTheWise wrote:
Here's the nitty-gritty of my detonation module creation:
Tolium: OQ 1000
Inert Gas: OQ 990
Copper: CD 901, OQ 996
Those resources allow me to experiment on the module up to 94%, which in turn makes rating 28 clusters, which in turn makes rating 57 bomb droids.
If you have time, I'd love to see community numbers!
Turns out if I substitute the 901/996 copper with 962/925, I get 96% experimentation and get up to 58-rated bomb droids! That I don't get...the ratings used is 50% from each stat, and the former copper should be better. Well, never look a gift horse in the mouth...
EnigmaBSc
Sat Apr 16, 2005 11:36 am
#29
If you use the following equation to calculate the experimentation from the resource quality then the results turn out exactly as you listed:
To illustrate:
Experimentation Properties = 50% CD, 50% OQ
Resource Quantities = 80 Tolium Reactive Gas, 40 Copper, 20 Inert Gas
Resources = Tolium Reactive Gas (OQ 1000, CD N/A), Copper (OQ 996, CD 901), Inert Gas (OQ 990, CD N/A)
Experimentation percentage = (((Tolium OQ × f(80, Tolium OQ) + Copper OQ × f(40, Copper OQ) + Inert Gas OQ × f(20, Inert Gas OQ)) / (f(80, Tolium OQ) + f(40, Copper OQ) + f(20, Inert Gas OQ))) × 50%) + (((Tolium CD × f(80, Tolium CD) + Copper CD × f(40, Copper CD) + Inert Gas CD × f(20, Inert Gas CD)) / ( f(80, Tolium CD) + f(40, Copper CD) + f(20, Inert Gas CD))) × 50%) / 10
Experimentation percentage = (((1000 × 80 + 996 × 40 + 990 × 20) / (80 + 40 + 20)) × 50%) + (((N/A × 0 + 901 × 40 + N/A × 0) / (0 + 40 + 0)) × 50%) / 10
Experimentation percentage = ((139640 / 140) × 50%) + ((36040 / 40) × 50%) / 10
Experimentation percentage = (997.429 × 50%) + (901 × 50%) / 10
Experimentation percentage = 949.214 / 10
Experimentation percentage = 94.921
And
Experimentation Properties = 50% CD, 50% OQ
Resource Quantities = 80 Tolium Reactive Gas, 40 Copper, 20 Inert Gas
Resources = Tolium Reactive Gas (OQ 1000, CD N/A), Copper (OQ 925, CD 962), Inert Gas (OQ 990, CD N/A)
Experimentation percentage = (((Tolium OQ × f(80, Tolium OQ) + Copper OQ × f(40, Copper OQ) + Inert Gas OQ × f(20, Inert Gas OQ)) / (f(80, Tolium OQ) + f(40, Copper OQ) + f(20, Inert Gas OQ))) × 50%) + (((Tolium CD × f(80, Tolium CD) + Copper CD × f(40, Copper CD) + Inert Gas CD × f(20, Inert Gas CD)) / ( f(80, Tolium CD) + f(40, Copper CD) + f(20, Inert Gas CD))) × 50%) / 10
Experimentation percentage = (((1000 × 80 + 925 × 40 + 990 × 20) / (80 + 40 + 20)) × 50%) + (((N/A × 0 + 962 × 40 + N/A × 0) / (0 + 40 + 0)) × 50%) / 10
Experimentation percentage = ((136800 / 140) × 50%) + ((38480 / 40) × 50%) / 10
Experimentation percentage = (977.142 × 50%) + (962 × 50%) / 10
Experimentation percentage = 969.571 / 10
Experimentation percentage = 96.957
Meaning that the conductivity of copper is weighted exactly the same as the overall quality of all the resources put together.
Hopefully this makes sense and other people can actually follow it!
EnigmaBSc
P.S. Sorry for stretching the page
Experimentation percentage = Sum over resource properties((Sum over resources(resource-property × f(resource-quantity, resource-property)) / Sum over resources(f(resource-quantity, resource-property))) × property-weight) / 10
where
{ resource-quantity if resource-property exists
f = {
{ 0 if resource-property does not exist
To illustrate:
Experimentation Properties = 50% CD, 50% OQ
Resource Quantities = 80 Tolium Reactive Gas, 40 Copper, 20 Inert Gas
Resources = Tolium Reactive Gas (OQ 1000, CD N/A), Copper (OQ 996, CD 901), Inert Gas (OQ 990, CD N/A)
Experimentation percentage = (((Tolium OQ × f(80, Tolium OQ) + Copper OQ × f(40, Copper OQ) + Inert Gas OQ × f(20, Inert Gas OQ)) / (f(80, Tolium OQ) + f(40, Copper OQ) + f(20, Inert Gas OQ))) × 50%) + (((Tolium CD × f(80, Tolium CD) + Copper CD × f(40, Copper CD) + Inert Gas CD × f(20, Inert Gas CD)) / ( f(80, Tolium CD) + f(40, Copper CD) + f(20, Inert Gas CD))) × 50%) / 10
Experimentation percentage = (((1000 × 80 + 996 × 40 + 990 × 20) / (80 + 40 + 20)) × 50%) + (((N/A × 0 + 901 × 40 + N/A × 0) / (0 + 40 + 0)) × 50%) / 10
Experimentation percentage = ((139640 / 140) × 50%) + ((36040 / 40) × 50%) / 10
Experimentation percentage = (997.429 × 50%) + (901 × 50%) / 10
Experimentation percentage = 949.214 / 10
Experimentation percentage = 94.921
And
Experimentation Properties = 50% CD, 50% OQ
Resource Quantities = 80 Tolium Reactive Gas, 40 Copper, 20 Inert Gas
Resources = Tolium Reactive Gas (OQ 1000, CD N/A), Copper (OQ 925, CD 962), Inert Gas (OQ 990, CD N/A)
Experimentation percentage = (((Tolium OQ × f(80, Tolium OQ) + Copper OQ × f(40, Copper OQ) + Inert Gas OQ × f(20, Inert Gas OQ)) / (f(80, Tolium OQ) + f(40, Copper OQ) + f(20, Inert Gas OQ))) × 50%) + (((Tolium CD × f(80, Tolium CD) + Copper CD × f(40, Copper CD) + Inert Gas CD × f(20, Inert Gas CD)) / ( f(80, Tolium CD) + f(40, Copper CD) + f(20, Inert Gas CD))) × 50%) / 10
Experimentation percentage = (((1000 × 80 + 925 × 40 + 990 × 20) / (80 + 40 + 20)) × 50%) + (((N/A × 0 + 962 × 40 + N/A × 0) / (0 + 40 + 0)) × 50%) / 10
Experimentation percentage = ((136800 / 140) × 50%) + ((38480 / 40) × 50%) / 10
Experimentation percentage = (977.142 × 50%) + (962 × 50%) / 10
Experimentation percentage = 969.571 / 10
Experimentation percentage = 96.957
Meaning that the conductivity of copper is weighted exactly the same as the overall quality of all the resources put together.
Hopefully this makes sense and other people can actually follow it!
EnigmaBSc
P.S. Sorry for stretching the page
Straker_Atrella
Sat Apr 16, 2005 11:40 am
#30
"Meaning that the conductivity of copper is weighted exactly the same as the overall quality of all the resources put together."
Wow, actually that is an awesome point.
I never actually broke down the math like that. Going to have to look at soem other stuff.
gamin
Sun Apr 17, 2005 8:54 pm
#31
so what kind of dmg do they actually do?
I made a 9 det. module, put it in a mse (not advanced) and gave some to my BH friend, on an NPC target it did 3100 dmg, nearly half the work for the BH!!
I thought that was pretty amazing!!
How are they in PvP - and does it do Blast Damage?
Ta'Vock-DE
gamin
Sun Apr 17, 2005 9:04 pm
#32
Also..
What do these things usualy sell for?
Thats quite alot of nice resources to blow up LoL
Ta'Vock-DE
Edit : okay, i just have all kinds of questions as I'm looking at this (I'm a new DE, yay!!)
an R3 can have 1 cluster
an R3 Adv 2 and a R2 Adv can have 3
so does only take one cluster to max your detenation str (59) or does it take 2 or 3 clusters to get the max
Message Edited by gamin on 04-17-2005 09:18 PM
RasalTheWise
Sun Apr 17, 2005 10:51 pm
#33
Wow, thanks for breaking that down, Enigma! The math lost me, but I'll take your word for it!
For the new DE: Use this formula to determine PvE damage (not sure if its confirmed, but its darn close):
150 x (detonation power) = Minimum Damage
200 x (detonation power) = Maximum Damage
Keep in mind that PvP damage is cut 75%. And an R3 chassis needs all modules filled to get the max rating. The rating of all the modules is cumulative. Also, the MSE droid chassis give you a +10 Detonation bonus.
For the new DE: Use this formula to determine PvE damage (not sure if its confirmed, but its darn close):
150 x (detonation power) = Minimum Damage
200 x (detonation power) = Maximum Damage
Keep in mind that PvP damage is cut 75%. And an R3 chassis needs all modules filled to get the max rating. The rating of all the modules is cumulative. Also, the MSE droid chassis give you a +10 Detonation bonus.
Napard
Mon Apr 18, 2005 2:36 pm
#34
gamin wrote:
Also..
What do these things usualy sell for?
Thats quite alot of nice resources to blow up LoL
Ta'Vock-DE
Edit : okay, i just have all kinds of questions as I'm looking at this (I'm a new DE, yay!!)
an R3 can have 1 cluster
an R3 Adv 2 and a R2 Adv can have 3
so does only take one cluster to max your detenation str (59) or does it take 2 or 3 clusters to get the max
Message Edited by gamin on 04-17-2005 09:18 PM
An R3 Adv can hold 6 modules in 2 combat capable socket clusters. 6 modules can yield a 59-rated det droid (depending on the resources you use).
An R3 regular can hold 3 modules in 1 cluster. 3 modules at the theoretical max of 30 detonation rating.
An R2 ADV can hold 5 modules - 3 in a cluster and two additionals. Theoretical max would be 50 detonation rating.
Point being, if you are going to go through the trouble of assembling a R-series detonation droid, just use the R3 ADV.
Kassuff
Mon Apr 18, 2005 3:14 pm
#35
My brain is not working today. Can someone translate this to a formula I can plug into excel? TIA
Drashk
Mon Apr 18, 2005 5:01 pm
#36
Might want to wait a couple of weeks. With the Combat Upgrade, the damage on detenation modules should be changing to fit with the way Health and armor play out.
Kassuff wrote:
My brain is not working today. Can someone translate this to a formula I can plug into excel? TIA
Napard
Tue Apr 19, 2005 6:45 am
#37
Enigma...I'm not sure about the formula. I plugged it into Excel and it says my resources yeild 98.15714% Experimentation. Since the detmods are rated up through 10 and I fully experiment, I'm assuming each module is rated a 9 (really, 9.815714 with out the decimcal being dropped). * 6, this equals a 58.89 rated det droid. But I consistently get 59 rated droids. My Tolium is 941OQ, Copper 1000CD/990OQ, Inert 998OQ.
BTW, for Excel, assuming Tolium OQ is cell C1, Tolium Quantity is D1, Copper CD is B2, Copper OQ is C2, Copper Quantity is D2, Inert Gas OQ C3, Inert Quantity is D3:
=(((((C1*D1)+(C2*D2)+(C3*D3))/SUM(D1
3))*0.5)+(B2*0.5))*0.1
Napard
Tue Apr 19, 2005 10:48 am
#39
I had the same thought, but I always thought the decimal was dropped (or, mathematically speaking, rounded down). Not that I am bitching...just want to know if I did something wrong. It would be nice to understand to calculate experimentation with other resources (non-uber).