Doctor Archive

Quick question for you guys out there. Lets say I have one organic with 906 Overall Quality and 966 Potential Energy, another with 985 Overall Quality and 733 Potential Energy, and another with 997 Overall Quality and 476 Potential Energy.

Now, when you craft a a biologoical effect controller or any other Stimpack, it says under experimental power that 66% is Overall Quality and 33% is Potential Energy.

My question now is which 1 of the 3 resources would be the best to use to reach the highest experimental power? How did you derive thatand what is your reasoning for choosing the resource? Again the resources are:

906 OQ - 966 PE

985 OQ - 733 PE

997 OQ - 476 PE

If it 66% for OQ and 33% for PE, the formula is (OQ*.66)+(PE*.33). The closer that number is to 1000 the better the overall resources is. So:

(906*.66) + (966*.33) = 916.74
(985*.66) + (733*.33) = 891.99
(997*.66) + (476*.33) = 815.10

You want to use the first one.

Absolutely correct, if you dont have a calculator ready or are gifted in the ways of math you can do like this, OQ is 2/3 and PE is 1/3

So OQ x 2 + PE x 1 the higher number is the better resource, max is 3000 this way