Artisan Archive

Good post Fluke. I had been figuring that I could bust out a calculator and figure out numerically which resources would be best for a given item, but figured I was too lazy to do the math.

Turns out, I am indeed too lazy to do the math

Here are the base equasions for maximum experimental effectiveness percentages obtainable by experimenting given only 1 variable for effectiveness

1) (r1 x q1) + (r2 x q2) + ... (rn x qn) / r1 + r2 + ... (rn) = aq

2) aq / 10 = meq

Where

rn = amout of resource n required

qn = quality of effect of resource n

aq = average quality

meq = maximum experimental quality

Example

I want to build X, it takes 10 units of minerals and uses conductivity as its experimental effectiveness statistic

I have 760 conductivity per unit

r1 = 10, q1= 760

10 x 760 /10 = 760

760 is average quality

760 /10 = 76

76% maximun experimental quality

In other wordsI can never get above 76% experimental effectiveness using these materials

More complicated example

I want to build couplers, I need 6 units of minerals, 4 chem

Stat used for experimental effectivness is Overall quality

Metal is 900 overall, chem is 600

r1= 6, q1= 900

r2= 4, q2 = 600

(6 x 900) + (4 x 600) / 10 = 780

780 = average quality

780 /10 = 78

78% is the maximum experimental quality of the coupler given the above ingredients

Will post on how to do this with multiple required qualities asap

Sava

Ok heres what you do for multipe required properties

1) do each property individually given the above equations

Then use the following formula

(meq1 x p1) + (meq2 x p2) + ... (meqn x pn) /100 = tme

Where

meqn= maximum experimental quality of property n

pn = percentage of quality used in total experimental effectivness of item ( see box on bottom right of schematic)

tme = total maximum experimental effectiveness

NOTE: p1 +p2 ... pn = 100 always because the sum of all pn is equal to 100% of the experimental effectiveness variables for multiple properties

Example

Device x has a maximum experimental effectiveness which is 75% overall quality (p1)and 25% conductivity (p2)

By using the equasions in post one we have previosly determined the total experimental quality of our resources.

Assume our overall quality was 67, our overall conductivity was 82

meq1= 67, p1 = 75

meq2= 82, p2 = 25

(67 x 75) + (82 x 25) / 100 = 70.75

tme = 70% The game rounds DOWN

The item we want to create, which has two variables in the maximum effectivenes equation, give the above numbers will have a maximum experimental effectivness of 70%

Sava