Architect Archive

What exactly does the % on the experimentation requirement means as far as the resource? Ok current schematics say:

Decay Resistance: 33%

Unit Toughness: 66%

So, does that mean that the resource you use has to have atleast 33% of DR, aka 330? Or does it mean that DR influences the finaly outcome by 33%?

Also "kgh extraction rate" assuming a 100% spot (for easeness sake) a 5kgh extractor pulls what? 500units/hour 50units/hour 5/units/hour? Or is it resource dependant? I.e. some minerals denser than others, there for more or less units=1kg?

Ok according to your stats:
Decay Resistance: 33%

Unit Toughness: 66%

Let's say the resource you are using has a DR of 900 and a UT of 500

Then the formula for it's actual effect on the finished product would be:

(900*.33)+(500*.66) = 297+300=627

The higher this number is the more initial experimentation points you start out with and the higher the end cap is that you can experiment it up too.

As a general rule of thumb 29% is the highest I've seen on the initial combine with 99% being about the highest you can experiment to (there are a few exceptions like repair tools)

Hope that helps.

My understanding is that the % factor that schematics list is how the reource affects the assembly outcome. This means the attributes influence the final outcome. IE 100% conductivity on tool with 820 CD copper means the final product can only be expiremented to 82%. Splitting theschematics attributes between 2 or 3 resource attributes works the same way. 33% decay would account for 33% of the final outcome. Using your example a resource that has 0 DR and 1000 UT would mean a final product that could be expiremented only to 66%.

The extration rates are these formulas straight from the FAQ:

Output per hour = Extraction rate in kg/h * 60 * density% = # units produced / hour
Output per day = Extraction rate in kg/h * 1440 * density% = # units / day

Example: A medium mineral harvester with an extraction rate of 6 kg/h on a 75% aluminum density will give you
= 6 * 60 * 0.75 = 270 units per hour production or 6480 per day

Hope this helps

Outstanding, thank you very much. I also found the answer to my other question in the FAQs. So both this matters are closed. Again, thank you.

HEhehe, sorry Ripster, I didnt ignore your post. You snuck in while I was typing my other reply. Thank you for taking the time tho .